The Fourier transform \( \mathcal{F} : \mathcal{S}'(\mathbb{R}^n) \to \mathcal{S}'(\mathbb{R}^n) \) is a homeomorphism .
[1, 7.15]References Link to heading
- W. Rudin, Functional analysis. McGraw-Hill, Inc., New York, 1991.
The Fourier transform \( \mathcal{F} : \mathcal{S}'(\mathbb{R}^n) \to \mathcal{S}'(\mathbb{R}^n) \) is a homeomorphism .
[1, 7.15]