Given a Riemannian manifold \((M,g)\), and a curve segment \(\gamma:[a,b]\to M\). Then, by Cauchy-Schwarz, follows
\[ E(\gamma)\ge \frac{1}{2(b-a)} L(\gamma)^2. \]Given a Riemannian manifold \((M,g)\), and a curve segment \(\gamma:[a,b]\to M\). Then, by Cauchy-Schwarz, follows
\[ E(\gamma)\ge \frac{1}{2(b-a)} L(\gamma)^2. \]